## Thomas' Calculus 13th Edition

Published by Pearson

# Chapter 5: Integrals - Section 5.2 - Sigma Notation and Limits of Finite Sums - Exercises 5.2 - Page 265: 13

#### Answer

$4\Sigma_{k=1} \frac{1}{2^{k}}$

#### Work Step by Step

as - k=Starting - 4 indicates How many times it will be performed -$\frac{1}{2^{k}}$ shows the form which has to be used put k=1,2,3,4 $4\Sigma_{k=1} \frac{1}{2^{k}}$=$\frac{1}{2}$ +$\frac{1}{4}$+$\frac{1}{8}$+$\frac{1}{16}$

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