Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 5: Integrals - Section 5.2 - Sigma Notation and Limits of Finite Sums - Exercises 5.2 - Page 265: 22

Answer

$\pi$

Work Step by Step

$5\Sigma _{k=1} \frac{\pi k}{15}$ =$\frac{\pi }{15}5\Sigma _{k=1} k$ =$\frac{\pi }{15}\frac{5(5+1)}{2} =\pi$
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