Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 5: Integrals - Section 5.2 - Sigma Notation and Limits of Finite Sums - Exercises 5.2 - Page 265: 16


=$5\Sigma_{k=1} (-1)^{k} \frac {k}{5}$

Work Step by Step

-Put k=1,2,3,4,5 into $\frac {k}{5}$ and it will be equal -- 1-$\frac{1}{5}$+$\frac{2}{5}$+$\frac{3}{5}$+$\frac{4}{5}$+$\frac{5}{5}$ --SIgma Notation Will be =$5\Sigma_{k=1} (-1)^{k} \frac {k}{5}$
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