Answer
a) 91
b) 819
c) 8281
Work Step by Step
a) $13\Sigma_{k=1} k =\frac{13(13+1}{2}$=91
b) $13\Sigma_{k=1} k^2 =\frac{13(13+1)(2(13)+1)}{6}$=819
c) $13\Sigma_{k=1} k^3 =[\frac{13(13+1)}{2}]^{2}$=91^2=8281
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 5: Integrals - Section 5.2 - Sigma Notation and Limits of Finite Sums - Exercises 5.2 - Page 265: 20
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