Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 10: Infinite Sequences and Series - Section 10.1 - Sequences - Exercises 10.1 - Page 570: 83

Answer

converges to $0$

Work Step by Step

As we know that $ \lim\limits_{n \to \infty} x^n=0$ Let $\lim\limits_{n \to \infty} a_n=\lim\limits_{n \to \infty} (\dfrac{1}{3})^n+\dfrac{1}{\sqrt {2^{n}}}$ This implies that $\lim\limits_{n \to \infty} a_n=\lim\limits_{n \to \infty} (\dfrac{1}{3})^n+\dfrac{1}{\sqrt {2^{n}}}$ and $\lim\limits_{n \to \infty} [(\dfrac{1}{3})^n+(\dfrac{1}{\sqrt 2})^n]=0+0=0$ Thus, {$a_n$} is Convergent and converges to $0$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.