Answer
converges to $1$
Work Step by Step
Let $\lim\limits_{n \to \infty} a_n= \lim\limits_{n \to \infty} (0.03)^{\frac{1}{n}}$
As we know that $\lim\limits_{n \to \infty} x^{\frac{1}{n}}=1$ when $x \gt 0$
This implies that $\lim\limits_{n \to \infty} a_n= \lim\limits_{n \to \infty} (0.03)^{\frac{1}{n}}=1$
Thus, $\lim\limits_{n \to \infty} a_n=1 $ and {$a_n$} converges to $1$
