Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 10: Infinite Sequences and Series - Section 10.1 - Sequences - Exercises 10.1 - Page 570: 60

Answer

converges to $0$

Work Step by Step

Let $\lim\limits_{n \to \infty} a_n= \lim\limits_{n \to \infty} [\ln n - \ln (n+1)]$ This implies that $\lim\limits_{n \to \infty} a_n= \lim\limits_{n \to \infty} [\ln n - \ln (n+1)]$ and $a_n=\lim\limits_{n \to \infty} \ln (\dfrac{n}{n+1}) =\ln \lim\limits_{n \to \infty} \dfrac{n}{(n+1)}=\ln (1)=0$ Thus, $\lim\limits_{n \to \infty} a_n=0$ and {$a_n$} converges to $0$.
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