Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Appendices - Section A.7 - Complex Numbers - Exercises A.7 - Page AP-34: 7

Answer

The graph is a circle with a center at $(-1,0)$ and a radius of $r=1.$ See details below.

Work Step by Step

$\begin{align*} \vert z+1\vert &= 1 \\ \vert (x+iy)+1\vert &= 1 \\ \vert (x+1) +iy\vert &= 1 \\ \sqrt{(x+1)^2 + y^2} &= 1 \\ (x+1)^2 + y^2 &= 1 \end{align*}$ The graph is a circle with a center at $(-1,0)$ and a radius of $r=1$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.