Answer
$2 \sec x \tan x+ 3 \sec^2 x+3 $
Work Step by Step
We have: $h(x)=2 \sec x+3 \tan x+3 x$
We need to differentiate both sides with respect to $x$.
$h^{\prime}(x)=2 (\sec x \tan x)+ 3 \sec^2 x+3 $
Therefore, $h^{\prime}(x)=2 \sec x \tan x+ 3 \sec^2 x+3 $
