Answer
$3 \cos ( 3x-5)$
Work Step by Step
We have: $f(x)=\sin ( 3x-5)$
We need to differentiate both sides with respect to $x$.
$f^{\prime}(x)= \cos ( 3x-5) \dfrac{d}{dx} ( 3x-5)\\=\cos ( 3x-5) \times ( 3)$
Therefore, $f^{\prime}(x)= 3 \cos ( 3x-5)$
