Answer
$j^{\prime}(x)=-2 \csc^2 x \cot x$
Work Step by Step
We have: $j(x)=\csc^2 x$
We need to differentiate both sides with respect to $x$.
$j^{\prime}(x)=2 \csc x \dfrac{d}{dx} [\csc x]\\=2 \csc x \times (\csc x \cot x)\\=-2 \csc^2 x \cot x$
Therefore, $j^{\prime}(x)=-2 \csc^2 x \cot x$
