Answer
$h^{\prime}(x)=-2 \csc x \cot x-\sec x \tan x + 3 $
Work Step by Step
We have: $h(x)=2 \csc x-\sec x+3x$
We need to differentiate both sides with respect to $x$.
$h^{\prime}(x)=2 (-\csc x \cot x)-\sec x \tan x + 3 $
Therefore, $h^{\prime}(x)=-2 \csc x \cot x-\sec x \tan x + 3 $
