## Calculus with Applications (10th Edition)

$5x(x^2-1)^{-1/2}(2x^2-\frac{1}{x^2-1})$
$10x^3(x^2-1)^{-1/2}-5x(x^2-1)^{1/2}$ greatest common factor is $5x(x^2-1)^{-1/2}$ $=[5x(x^2-1)^{-1/2}].2x^2-[5x(x^2-1)^{-1/2}].(x^2-1)^{-1}$ $=5x(x^2-1)^{-1/2}(2x^2-\frac{1}{x^2-1})$