Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter R - Algebra Reference - R.6 Exponents - R.6 Exercises - Page R-25: 11



Work Step by Step

RECALL: (i) $\dfrac{a^m}{a^n} = a^{m-n}$ (ii) $a^{m} \cdot a^{n} = a^{m+n}$ (ii) $a^{-m} = \dfrac{1}{a^m}, a\ne0$ Use rule (ii) above to have: $=\dfrac{10^{8+(-10)}}{10^{4+2}} \\=\dfrac{10^{-2}}{10^{6}}$ Use rule (i) above to have: $=10^{-2-6} \\=10^{-8}$ Use rule (iii) to have: $=\dfrac{1}{10^8} \\=\dfrac{1}{100,000,000} \\=0.00000001$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.