Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter R - Algebra Reference - R.6 Exponents - R.6 Exercises: 50

Answer

$\displaystyle \frac{m^{3}p}{n}$

Work Step by Step

$\displaystyle \frac{m^{7/3}\cdot n^{-2/5}.\cdot p^{3/8}}{m^{-2/3}\cdot n^{3/5}p^{-5/8}}=\qquad$ ....... use $\displaystyle \frac{a^{m}}{a^{n}}=a^{m-n}$ $=m^{7/3-(-2/3)}\cdot n^{-2/5-(3/5)}\cdot p^{3/8-(-5/8)}$ ... simplify exponents $=m^{9/3}n^{-5/5}p^{8/8}$ $=m^{3}n^{-1}p^{1}\qquad$ ....... use $a^{-n}=\displaystyle \frac{1}{a^{n}}=(\frac{1}{a})^{n}$ $=\displaystyle \frac{m^{3}p}{n}$
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