## Calculus with Applications (10th Edition)

$\displaystyle \frac{m^{3}p}{n}$
$\displaystyle \frac{m^{7/3}\cdot n^{-2/5}.\cdot p^{3/8}}{m^{-2/3}\cdot n^{3/5}p^{-5/8}}=\qquad$ ....... use $\displaystyle \frac{a^{m}}{a^{n}}=a^{m-n}$ $=m^{7/3-(-2/3)}\cdot n^{-2/5-(3/5)}\cdot p^{3/8-(-5/8)}$ ... simplify exponents $=m^{9/3}n^{-5/5}p^{8/8}$ $=m^{3}n^{-1}p^{1}\qquad$ ....... use $a^{-n}=\displaystyle \frac{1}{a^{n}}=(\frac{1}{a})^{n}$ $=\displaystyle \frac{m^{3}p}{n}$