## Calculus with Applications (10th Edition)

Published by Pearson

# Chapter R - Algebra Reference - R.6 Exponents - R.6 Exercises - Page R-25: 24

#### Answer

$\displaystyle \frac{3n^{2}+4m}{mn^{2}}$

#### Work Step by Step

$(\displaystyle \frac{m}{3})^{-1}+(\frac{n}{2})^{-2}$=.........$(\displaystyle \frac{a}{b})^{m}=\frac{a^{m}}{b^{m}}$ $=\displaystyle \frac{m^{-1}}{3^{-1}}+\frac{n^{-2}}{2^{-2}}$=.........$\displaystyle \frac{1}{a^{n}}=a^{-n}$ $=\displaystyle \frac{3^{1}}{m^{1}}+\frac{2^{2}}{n^{2}}$ $=\displaystyle \frac{3}{m}+\frac{4}{n^{2}}$=........common denominator =$mn^{2}$ ........ $=\displaystyle \frac{3n^{2}}{mn^{2}}+\frac{4m}{mn^{2}}$ $=\displaystyle \frac{3n^{2}+4m}{mn^{2}}$

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