Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter R - Algebra Reference - R.6 Exponents - R.6 Exercises - Page R-25: 30



Work Step by Step

$-125^{\frac{2}{3}} = -\left(125^{\frac{1}{3}}\right)^2$ Note that: $125^{\frac{1}{3}}=5$ since $5^3 = 125$ Thus, $ -\left(125^{\frac{1}{3}}\right)^2=-(5)^2=-25$
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