Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter R - Algebra Reference - R.6 Exponents - R.6 Exercises: 33

Answer

$\displaystyle \frac{1}{16}$

Work Step by Step

$8^{-4/3}=$ ... recognize $8=2^{3}$ $=(2^{3})^{-4/3}=$ ...use: $(a^{m})^{n}=a^{mn}$ $=2^{-4}=$ ...use: $\displaystyle \frac{1}{a^{n}}=a^{-n}$ $=\displaystyle \frac{1}{2^{4}}$ $= \displaystyle \frac{1}{16}$
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