Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter R - Algebra Reference - R.6 Exponents - R.6 Exercises: 10

Answer

$32,768$

Work Step by Step

RECALL: (i) $\dfrac{a^m}{a^n} = a^{m-n}$ (ii) $a^{m} \cdot a^{n} = a^{m+n}$ Use rule (ii) above to have: $=\dfrac{8^{9+(-7)}}{8^{-3}} \\=\dfrac{8^{2}}{8^{-3}}$ Use rule (i) above to have: $=8^{2-(-3)} \\=8^{2+3} \\=8^5 \\=32,768$
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