Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter R - Algebra Reference - R.6 Exponents - R.6 Exercises - Page R-25: 42


$\displaystyle \frac{b}{a^{3}}$

Work Step by Step

$[\displaystyle \frac{a^{-7}b^{-1}}{b^{-4}a^{2}}]^{1/3}$ =...... use: $\displaystyle \frac{a^{m}}{a^{n}}=a^{m-n}$ =$[a^{-7-2}b^{-1-(-4)}]^{1/3}$ $=(a^{-9}b^{3})^{1/3}$ =...... use: $(ab)^{m}=a^{m}b^{m}$ $=(a^{-9})^{1/3}(b^{3})^{1/3}$ =...... use: $(a^{m})^{n}=a^{mn}$ $=a^{-3}b^{1}$ =......use: $\displaystyle \frac{1}{a^{n}}=a^{-n}$ $= \displaystyle \frac{b}{a^{3}}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.