Answer
$2t^3-4t^2+7t+C$
Work Step by Step
$\int(6t^2-8t+7)dt$
$=\int 6t^2dt-\int 8tdt+\int 7dt$
$=6\int t^2dt-8\int t^1dt+7\int t^0dt$
$=6*\frac{t^3}{3}-8*\frac{t^2}{2}+7*\frac{t^1}{1}+C$
$=2t^3-4t^2+7t+C$
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