Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 7 - Integration - 7.1 Antiderivatives - 7.1 Exercises: 6

Answer

$9y+C$

Work Step by Step

Since $y^0=1$, we can write $9$ as $9y^0$ and use the Power Rule: $\int 9 dy$ $=\int 9y^0dy$ $=9\int y^0dy$ $=9*\frac{y^1}{1}+C$ $=9y+C$
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