Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 7 - Integration - 7.1 Antiderivatives - 7.1 Exercises - Page 366: 53

Answer

p=$175 - 0.01x - 0.01x^{2}$

Work Step by Step

R(x)= $\int (175 - 0.02x - 0.03x^{2})dx$ = $175x - 0.01x^{2} - 0.01x^{3} + C$ To find the C, we know R(0)=0 since if no items are sold, the revenue is 0. So: $0 = 175(0) = 0.01(0)^{2} - 0.01(0)^{3} + C$ $C = 0$ Thus, the revenue function is: R(x) = $175x - 0.01x^{2} - 0.01x^{3}$ Recall that R= qp, where p is the demand function giving the price p as a function of q. Then $175x - 0.01x^{2} - 0.01x^{3} = xp$ $\frac{175x - 0.01x^{2} - 0.01x^{3}}{x} = p$ The demand function is p=$175 - 0.01x - 0.01x^{2}$
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