Answer
$\frac{5x^3}{3}-3x^2+3x+C$
Work Step by Step
$\int(5x^2-6x+3)dx$
$=\int 5x^2dx-\int 6xdx+\int 3dx$
$=5\int x^2dx-6\int x^1 dx+3\int x^0dx$
$=5*\frac{x^3}{3}-6*\frac{x^2}{2}+3*\frac{x^1}{1}+C$
$=\frac{5x^3}{3}-3x^2+3x+C$
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