Answer
\[{z^4} + {z^3} + {z^2} - 6z + C\]
Work Step by Step
\[\begin{gathered}
\int_{}^{} {\,\,\,\left( {4{z^3} + 3{z^2} + 2z - 6} \right)dz} \hfill \\
Integrate\,\,,\,\,use\,\,the\,\,power\,\,rule \hfill \\
\int_{}^{} {{z^n}dz} = \frac{{{z^{n + 1}}}}{{n + 1}} + C \hfill \\
For\,\,each\,\,term\,,\,Then \hfill \\
= 4\,\left( {\frac{{{z^4}}}{4}} \right) + 3\,\left( {\frac{{{z^3}}}{3}} \right) + 2\,\left( {\frac{{{z^2}}}{2}} \right) - 6\,\left( z \right) + C \hfill \\
Simplify \hfill \\
{z^4} + {z^3} + {z^2} - 6z + C \hfill \\
\end{gathered} \]