Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 7 - Integration - 7.1 Antiderivatives - 7.1 Exercises - Page 366: 7



Work Step by Step

$\int (2z+3)dz$ $=\int 2zdz+\int 3dz$ $=2\int z^1dz+3\int z^0 dz$ $=2*\frac{z^2}{2}+3*\frac{z^1}{1}+C$ $=z^2+3z+C$
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