Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 7 - Integration - 7.1 Antiderivatives - 7.1 Exercises - Page 366: 8



Work Step by Step

$\int (3x-5)dx$ $=\int 3xdx-\int 5dx$ $=3\int x^1dx-5\int x^0dx$ $=3*\frac{x^2}{2}-5*\frac{x^1}{1}+C$ $=\frac{3x^2}{2}-5x+C$
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