Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 2 - Nonlinear Functions - Chapter Review - Review Exercises - Page 114: 94

Answer

It takes 11 years for $\$1000$ deposited at $\%6$ compounded semiannually to double. And takes 11 years for $\$1000$ deposited at $\%6$ compounded semiannually to triple.

Work Step by Step

Use the formula for compound interest with $P=\$1000$ $r=0.06$ $m=2$ To double: $A=P(1+\frac{r}{m})^{tm}$ $2000=1000(1+\frac{0.06}{2})^{2t}$ $(1+\frac{0.06}{2})^{2t}=2$ $2t=\log_{1.03}2$ $2t = 23.45$ $t \approx 11.72 \approx 11$ To triple: $A=P(1+\frac{r}{m})^{tm}$ $3000=1000(1+\frac{0.06}{2})^{2t}$ $(1+\frac{0.06}{2})^{2t}=3$ $2t=\log_{1.03}3$ $2t =37.167$ $t \approx 18.58 \approx 18$
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