## Calculus with Applications (10th Edition)

$p\approx 1.830\qquad$or $p\approx-6.830$
$[1+\displaystyle \frac{2p}{5}]^{2}=3\qquad \color{blue}{\text{ ...take the square root from both sides } }$ $1+\displaystyle \frac{2p}{5}=\pm\sqrt{3}$ $\displaystyle \frac{5+2p}{5}=\pm\sqrt{3}\qquad \color{blue}{\text{ ... }/\times 5 }$ $5+2p=\pm 5\sqrt{3}\qquad \color{blue}{\text{ ... }/-5 }$ $2p=-5\pm\sqrt{3}\qquad \color{blue}{\text{ ... }/\div 2 }$ $p=\displaystyle \frac{-5\pm 5\sqrt{3}}{2}$ $p=\displaystyle \frac{-5+5\sqrt{3}}{2}\approx 1.830\qquad$or $p=\displaystyle \frac{-5-5\sqrt{3}}{2}\approx-6.830$