Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 2 - Nonlinear Functions - Chapter Review - Review Exercises - Page 114: 66

Answer

$1.5$

Work Step by Step

For $a>0, a\neq 1$, and $x>0,\qquad y=\log_{a}x$ means $a^{y}=x$. $.................................$ $ \log_{100}1000=x$ means $100^{x}=1000$, $100^{x}=1000$ $(10^{2})^{x}=10^{3}$ $10^{2x}=2^{3}\qquad \color{blue}{\text{ ...equate the exponents } }$ $2x=3$ $x=\displaystyle \frac{3}{2}=1.5$ With change of base, $\displaystyle \log_{a}x=\frac{\log_{b}x}{\log_{b}a}=\frac{\ln x}{\ln a}$, using a calculator, $\log_{100}1000$=$\displaystyle \frac{\ln 1000}{\ln 100}=1.5$
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