Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 2 - Nonlinear Functions - Chapter Review - Review Exercises - Page 114: 75



Work Step by Step

$e^{-5-2x}=5 \qquad \color{blue}{\text{ ...apply ln(...) to both sides } }$ $\ln e^{-5-2x}=\ln 5 \qquad \color{blue}{\text{ ...apply } \log_{a}a^{x}=x}$ $-5-2x=\ln 5$ $-2x=\ln 5+5\qquad \color{blue}{\text{ ... } /\div(-2)}$ $x=\displaystyle \frac{\ln 5+5}{-2}$ $x\approx-3.305$
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