Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 2 - Nonlinear Functions - Chapter Review - Review Exercises - Page 114: 76


$x\approx 1.213$

Work Step by Step

$e^{3x-1}=14\qquad \color{blue}{\text{ ...apply ln(...) to both sides } }$ $\ln(e^{3x-1})=\ln 14\qquad \color{blue}{\text{ ...apply } \log_{a}a^{x}=x}$ $3x-1=\ln 14$ $3x=1+\ln 14$ $x=\displaystyle \frac{1+\ln 14}{3}$ $x\approx 1.213$
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