Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 2 - Nonlinear Functions - Chapter Review - Review Exercises - Page 114: 74

Answer

$k\approx-0.884$

Work Step by Step

$12^{-k}=9 \qquad \color{blue}{\text{ ...apply ln(...) to both sides } }$ $\ln 12^{-k}=\ln 9 \qquad \color{blue}{\text{ ...apply } \log_{a}x^{r}=r\log_{a}x}$ $-k\ln 12=\ln 9 \qquad \color{blue}{\text{ ... } /\div(-\ln 12)}$ $k=-\displaystyle \frac{\ln 9}{\ln 12}$ $k\approx-0.884$
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