Chapter 2 - Nonlinear Functions - Chapter Review - Review Exercises - Page 114: 79

$k=2$

$\log_{k}64=6\qquad \color{blue}{\text{ ...apply to both sides: } k^{(...)},\quad }$ $k^{\log_{k}64}=k^{6}\qquad \color{blue}{\text{ ...apply } a^{\log_{a}x}=x}$ $64=k^{6}$ $2^{6}=k^{6}\qquad \color{blue}{\text{ ...Exponents are equal. Equate the bases } }$ $k=2$