Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 2 - Nonlinear Functions - Chapter Review - Review Exercises - Page 114: 73

Answer

$m\approx-1.807$

Work Step by Step

$2^{1-m}=7\qquad \color{blue}{\text{ ...apply ln(...) to both sides } }$ $\ln 2^{1-m}=\ln 7\qquad \color{blue}{\text{ ...apply } \log_{a}x^{r}=r\log_{a}x}$ $(1-m)\ln 2=\ln 7\qquad \color{blue}{\text{ ... } /\div\ln 2}$ $1-m=\displaystyle \frac{\ln 7}{\ln 2}$ $1-\displaystyle \frac{\ln 7}{\ln 2}=m$ $m\approx-1.807$
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