Answer
$\log_{5}(21k^{4})$
Work Step by Step
$\log_{5}3k+\log_{5}7k^{3}=\qquad \color{blue}{\text{ ...apply } \log_{a}xy=\log_{a}x+\log_{a}y}$
$=\log_{5}(3k\cdot 7k^{3})$
$=\log_{5}(21k^{4})$
Calculus with Applications (10th Edition)
by Lial, Margaret L.; Greenwell, Raymond N.; Ritchey, Nathan P.
Published by
Pearson
ISBN 10:
0321749006
ISBN 13:
978-0-32174-900-0
Chapter 2 - Nonlinear Functions - Chapter Review - Review Exercises - Page 114: 67
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