Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 3 - Derivatives - 3.4 The Product and Quotient Rules - 3.4 Exercises - Page 160: 44

Answer

$g'(t)=e^{\frac{t}{2}}(2+t)$

Work Step by Step

$g(t)=2te^{\frac{t}{2}}$ Product Rule: $g'(t)=(2)(e^{\frac{t}{2}})+ (2t)(\frac{1}{2}e^{\frac{t}{2}}) = e^{\frac{t}{2}}(2+t)$
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