Answer
$g'(t) = 6t - \frac{42}{t^8}$
Work Step by Step
$g(t) = 3t^2+\frac{6}{t^7} = 3t^2 + 6t^{-7}$
Power rule: $g'(t) = 3(2)t^{(2-1)} + 6(-7)t^{(-7-1)} = 6t - \frac{42}{t^8}$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 3 - Derivatives - 3.4 The Product and Quotient Rules - 3.4 Exercises - Page 160: 39
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