Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 3 - Derivatives - 3.4 The Product and Quotient Rules - 3.4 Exercises - Page 160: 40

Answer

$y' = 2w-\frac{1}{w^2}$

Work Step by Step

First Separate Into 3 Different Fractions to Make Differentiation Easier: $y = \frac{w^4+5w^2+w}{w^2} = w^2 + 5 + w^{-1}$ Power Rule: $y'=1(2)w^{(2-1)}+5(0)w^{(0-1)} + 1(-1)w^{(-1-1)} = 2w-w^{-2}=2w-\frac{1}{w^2}$
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