Answer
$f'(x)= \frac{e^x}{(e^x+1)^2}$
Work Step by Step
$f(x) = \frac{e^x}{e^x + 1}$
Quotient Rule:
$f'(x)=\frac{(e^x)(e^x+1)-(e^x)(e^x)}{(e^x+1)^2} = \frac{e^{2x}+e^x-e^{2x}}{(e^x+1)^2} = \frac{e^x}{(e^x+1)^2}$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 3 - Derivatives - 3.4 The Product and Quotient Rules - 3.4 Exercises - Page 160: 21
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