Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 3 - Derivatives - 3.4 The Product and Quotient Rules - 3.4 Exercises - Page 160: 19


$f'(x)= \frac{1}{(x+1)^2}$

Work Step by Step

$f(x) = \frac{x}{x+1}$ Quotient Rule: $f'(x) = \frac{(1)(x+1)-(1)(x)}{(x+1)^2} = \frac{x+1-x}{(x+1)^2} = \frac{1}{(x+1)^2}$
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