Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 3 - Derivatives - 3.4 The Product and Quotient Rules - 3.4 Exercises - Page 160: 27



Work Step by Step

$\left(\frac{f}{g}\right)'$ = $\frac{f'g-fg'}{g^2}$ $\left(\frac{e^x}{x^2-1}\right)'$ = $\frac{(e^x)(x^2-1)-(e^x)(2x)}{(x^2-1)^2}$
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