Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 3 - Derivatives - 3.4 The Product and Quotient Rules - 3.4 Exercises: 27

Answer

$\frac{(e^x)(x^2-1)-(e^x)(2x)}{(x^2-1)^2}$

Work Step by Step

$\left(\frac{f}{g}\right)'$ = $\frac{f'g-fg'}{g^2}$ $\left(\frac{e^x}{x^2-1}\right)'$ = $\frac{(e^x)(x^2-1)-(e^x)(2x)}{(x^2-1)^2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.