Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 3 - Derivatives - 3.4 The Product and Quotient Rules - 3.4 Exercises: 24

Answer

$\frac{1-2x}{2\sqrt x \times e^x}$

Work Step by Step

$(\frac{f}{g})'$ = $\frac{f'g-fg'}{g^2}$ $e^{-x}\sqrt x$ = $\frac{\sqrt x}{e^x}$ $(\frac{\sqrt x}{e^x})'$ = $\frac{(\frac{1}{2\times\sqrt x})(e^x)-(\sqrt x)(e^x)}{(e^x)^2}$ = $\frac{e^x-(e^x)(2x)}{2\sqrt x \times e^{2x}}$ = $\frac{1-2x}{2\sqrt x \times e^x}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.