#### Answer

$f'(x) = 6x+1$

#### Work Step by Step

Using Product Rule:
$f(x) = (x-1)(3x+4)$
$f'(x) = (1)(3x+4)+(x-1)(3) = 3x+4+3x-3=6x+1$
Expansion First and then Power Rule:
$f(x) = (x-1)(3x+4) = 3x^2+x-4$
$f'(x)=3(2)x^{2-1}+(1)x^{1-1}-4(0)x^{0-1} = 6x+1$