Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 3 - Derivatives - 3.4 The Product and Quotient Rules - 3.4 Exercises - Page 160: 38

Answer

$y' = \frac{-12}{p^4}$

Work Step by Step

$y = \frac{4}{p^3} = 4p^{-3}$ Power rule: $y' = 4(-3)p^{(-3-1)} = \frac{-12}{p^4}$
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