Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 8 - Techniques of Integration - Chapter Review Exercises - Page 460: 59

Answer

$$\frac{1}{2}\sinh 2. $$

Work Step by Step

We have $$ \int_0^1\cosh 2t dt=\frac{1}{2} \int_0^12\cosh 2t \ dt\\ = \frac{1}{2}\sinh 2t|_0^1=\frac{1}{2}(\sinh 2-\sinh 0)=\frac{1}{2}\sinh 2. $$
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