Answer
$$\frac{1}{2}\sin ^{4} \theta+C$$
Work Step by Step
\begin{aligned} \int \sin 2 \theta \sin ^{2} \theta d \theta &=\int(2 \sin \theta \cos \theta) \sin ^{2} \theta d \theta \\ &=2 \int \sin ^{3} \theta \cos \theta d \theta\\
&=\frac{1}{2}\sin ^{4} \theta+C
\end{aligned}