Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 8 - Techniques of Integration - Chapter Review Exercises - Page 460: 20

Answer

$$\frac{1}{2}\sin ^{4} \theta+C$$

Work Step by Step

\begin{aligned} \int \sin 2 \theta \sin ^{2} \theta d \theta &=\int(2 \sin \theta \cos \theta) \sin ^{2} \theta d \theta \\ &=2 \int \sin ^{3} \theta \cos \theta d \theta\\ &=\frac{1}{2}\sin ^{4} \theta+C \end{aligned}
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