Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 8 - Techniques of Integration - Chapter Review Exercises - Page 460: 10

Answer

$$\frac{1}{2}\ln |x^2+1|+C$$

Work Step by Step

We integrate as follows: \begin{align*} \int \frac{d x}{x+x^{-1}}&=\int \frac{d x}{x+\frac{1}{x}}\\ &=\int \frac{xd x}{x^2+1}\\ &=\frac{1}{2}\ln |x^2+1|+C \end{align*}
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