Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 8 - Techniques of Integration - 8.4 Integrals Involving Hyperbolic and Inverse Hyperbolic Functions - Exercises - Page 415: 25

Answer

$$\sinh ^{-1}(1)$$

Work Step by Step

\begin{aligned} \int_{0}^{1} \frac{1}{\sqrt{1+x^{2}}} d x &=\left.\sinh ^{-1} x\right|_{0} ^{1} \\ &=\sinh ^{-1}(1)-\sinh ^{-1}(0) \\ &=\sinh ^{-1}(1)-0 \\ &=\sinh ^{-1}(1) \end{aligned}
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