Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 8 - Techniques of Integration - 8.4 Integrals Involving Hyperbolic and Inverse Hyperbolic Functions - Exercises - Page 415: 24

Answer

$$\operatorname{coth}^{-1}(5)-\operatorname{coth}^{-1}(4)$$

Work Step by Step

\begin{aligned} \int_{4}^{5} \frac{1}{\left(1-x^{2}\right)} d x &=\left.\operatorname{coth}^{-1} x\right|_{4} ^{5} \\ &=\operatorname{coth}^{-1}(5)-\operatorname{coth}^{-1}(4) \end{aligned}
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